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I understand the Jewish birthday is calculated on the lunar year, which could cause the birthday to drift back and fourth along the lunar calendar. But supposing the child was born, say, first day of Sukkot, would his birthday be forever tied to that holiday to make calculations easier?

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Do you mean "drift back and forth along the solar calendar"? –  Double AA Jan 19 at 8:34

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Yes, someone born on a certain Hebrew-calendar date will have the same calendar date as his birthday every year. Thus, some one born on a red-letter day that is the same date every year, like the first day of Sukos, will have that as his birthday. (In fact, I have seen yahrzeit plaques that indicate "1st of Sukos" or the like instead of a date.)

Some red-letter dates vary, however, like most fasts (which change date if they occur on Shabas), Shavuos (which nowadays is the 6th of Sivan but won't always be), and some others. The birthday follows the calendar date, not the red-letter day.

Exceptions to the above rule show up

  • when someone is born on the 30th day of Marcheshvan or Kislev and his birthday is in a year that that date doesn't exist;
  • when someone is born on the 1st day of Kislev or Teves when the preceding day is the 29th of Marcheshvan or Kislev, and his birthday is in a year that Marcheshvan or Kislev has 30 days; and
  • when someone is born in Adar, and either he's born in a leap year or his birthday is in a leap year.

For those cases, see e.g. http://download.yutorah.org/2013/1053/Purim_To_Go_-_5771_Rabbi_Willig.pdf.

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"Zos Chanukah" is another example of a red-letter day whose calendar date varies. –  Double AA Jan 19 at 8:34

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